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The particle executing simple harmonic motion has a kinetic energy `K_(0) cos^(2) omegat`. The maximum values of the potential energy and the total energy are respectively:

A

`K_(0)//2 and K_(0)`

B

`K_(0) and 2K_(0)`

C

`K_(0) and K_(0)`

D

`0 and 2K_(0)`

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To solve the problem, we need to analyze the kinetic energy of a particle executing simple harmonic motion (SHM) given by the equation \( K(t) = K_0 \cos^2(\omega t) \). We will find the maximum values of the potential energy and the total energy. ### Step-by-Step Solution: 1. **Understanding Kinetic Energy in SHM**: The kinetic energy of a particle in SHM is given by the equation \( K(t) = \frac{1}{2}mv^2 \), where \( m \) is the mass and \( v \) is the velocity of the particle. In this case, we are given that \( K(t) = K_0 \cos^2(\omega t) \). 2. **Finding Maximum Kinetic Energy**: The maximum value of \( K(t) \) occurs when \( \cos^2(\omega t) \) is at its maximum, which is 1. Therefore, the maximum kinetic energy \( K_{\text{max}} \) can be calculated as: \[ K_{\text{max}} = K_0 \cdot 1 = K_0 \] 3. **Relationship Between Kinetic and Potential Energy**: In SHM, the total mechanical energy \( E \) is the sum of kinetic energy \( K \) and potential energy \( U \): \[ E = K + U \] The total energy in SHM is constant and is equal to the maximum kinetic energy or maximum potential energy. 4. **Finding Maximum Potential Energy**: Since the maximum kinetic energy is \( K_{\text{max}} = K_0 \), the maximum potential energy \( U_{\text{max}} \) is also equal to \( K_0 \) because in SHM: \[ U_{\text{max}} = K_{\text{max}} = K_0 \] 5. **Calculating Total Energy**: The total energy \( E \) in SHM is equal to the maximum kinetic energy (or potential energy): \[ E = K_{\text{max}} = K_0 \] 6. **Final Results**: Therefore, the maximum values of potential energy and total energy are both \( K_0 \). ### Conclusion: The maximum values of the potential energy and the total energy are respectively: - Maximum Potential Energy \( U_{\text{max}} = K_0 \) - Total Energy \( E = K_0 \)

To solve the problem, we need to analyze the kinetic energy of a particle executing simple harmonic motion (SHM) given by the equation \( K(t) = K_0 \cos^2(\omega t) \). We will find the maximum values of the potential energy and the total energy. ### Step-by-Step Solution: 1. **Understanding Kinetic Energy in SHM**: The kinetic energy of a particle in SHM is given by the equation \( K(t) = \frac{1}{2}mv^2 \), where \( m \) is the mass and \( v \) is the velocity of the particle. In this case, we are given that \( K(t) = K_0 \cos^2(\omega t) \). 2. **Finding Maximum Kinetic Energy**: ...
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