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The phase difference between the instant...

The phase difference between the instantaneous velocity and acceleration of a particle executing simple harmonic motion is:

A

`pi`

B

`0.707pi`

C

Zero

D

`0.5pi`

Text Solution

Verified by Experts

The correct Answer is:
D
General equation for particle displacement
`x=x_(0)sinomegat`
Velocity for particle
`V=(dx)/(dt)=omegaV_(0)cosomegat`
Acceleration of a particle
`a=(dv)/(dt)=-a_(0)omega^(2)sinomegat`
`a=+omega^(2)a_(0)cos[(pi)/(2)+omegat]`
Phase difference `(Deltaphi)=(pi)/(2)`
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