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A particle moves in a circle of radius 5...

A particle moves in a circle of radius 5 cm with constant speed and time period `0.2pi`. The acceleration of the particle is:

A

`15m//s^(2)`

B

`25m//s^(2)`

C

`36m//s^(2)`

D

`5m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
Acceleration `=omega^(2)Randomega=((2pi)/(T))`
`=((2pi)/(T))^(2)xxR`
`=((2pi)/(0.2pi))^(2)xx(5)/(100)=5m//s^(2)`
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