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Moment of inertia of a circular ring abo...

Moment of inertia of a circular ring about an axis through its centre and perpendicular to its plane is

A

`I = (1)/(2) MR^2`

B

`I = MR^2`

C

`I = (3)/(2) MR^2`

D

`I = (5)/(2) MR^2`

Text Solution

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The correct Answer is:
B
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