The area bounded between the parabolas `x^2=y/4"and"x^2=9y` and the straight line `y""=""2` is (1) `20sqrt(2)` (2) `(10sqrt(2))/3` (3) `(20sqrt(2))/3` (4) `10sqrt(2)`

Find the area bounded by the parabola y^2=4x and the straight line x+y=3 .

The area bounded by the parabola y=4x^(2),y=(x^(2))/(9) and the line y = 2 is

Find the area bounded by the curves x^2+y^2=4, x^2=-sqrt2 y and x=y

Find the area bounded by the curves x^2+y^2=4, x^2=-sqrt2 y and x=y

The graph of straight line y = sqrt(3)x + 2sqrt(3) is :

The area bounded by the curves y""=""cos""x""a n d""y""="sin""x between the cordinates x""=""0""a n d""x""=(3pi)/2 is (1) 4sqrt(2)-""2 (2) 4sqrt(2)""1 (3) 4sqrt(2)+""1 (4) 4sqrt(2)""2

The distance of the point (1, 2, 3) from the plane x+y-z=5 measured along the straight line x=y=z is 5sqrt(3) (2) 10sqrt(3) (3) 3sqrt(10) 3sqrt(5) (5) 2sqrt(5)

The shortest distance between line y"-"x""=""1 and curve x""=""y^2 is : (1) (sqrt(3))/4 (2) (3sqrt(2))/8 (3) 8/(3sqrt(2)) (4) 4/(sqrt(3))

The shortest distance between the parabola y^2 = 4x and the circle x^2 + y^2 + 6x - 12y + 20 = 0 is : (A) 0 (B) 1 (C) 4sqrt(2) -5 (D) 4sqrt(2) + 5

Show that the area included between the parabolas y^2 = 4a(x + a) and y^2 = 4b(b - x) is 8/3 sqrt(ab) (a+b).