Solve `log(-x)=2log(x+1)dot`

Explanation

`log(-x) = 2log(x+1)`

Here, `-x` should be negative as we can have log of only positive numbers.

`:. -x gt 0 and x+1 gt 0`

`=>x le 0 and x gt -1`

`:. x in (-1,0)->(1)`

Now, `log(-x) = 2log(x+1)`

`=>log(-x) = log(x+1)^2`

`=>-x = (x+1)^2`

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