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Let a ,b ,c be real numbers with a^2+...

Let `a ,b ,c` be real numbers with `a^2+b^2+c^2=1.` Show that the equation `|a x-b y-c b x-a y c x+a b x+a y-a x+b y-cc y+b c x+a c y+b-a x-b y+c|=0` represents a straight line.

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