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An ordinary cube has 4 blank faces, one ...

An ordinary cube has 4 blank faces, one face mark 2 and another marked 3, then the probability of obtaining 12 in 5 throws is

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The correct Answer is:
`(5)/(2592)`

The total number of ways in `n = 6^(5)`. A total of 12 in 5 throw can be obtained in following two ways:
(i) one blank and four 3's can be obtained in `.^(5)C_(1)=5` ways.
(ii) three 2's and two 3's can be obtained in `.^(5)C_(2) = 10` ways.
Hence, the required probability is `15//6^(5) = 5//2592`.
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CENGAGE-PROBABILITY I -Exercise 9.2
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