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The point of intersection of the lines `(x-5)/3=(y-7)/(-1)=(z+2)/1a n d=(x+3)/(-36)=(y-3)/2=(z-6)/4` is a. `(21 ,5/3,(10)/3)` b. `(2,10 ,4)` c. `(-3,3,6)` d. `(5,7,-2)`

A

`(21,(5)/(3),(10)/(3))`

B

(2,10,4)

C

(-3,3,6)

D

(5,7,-2)

Text Solution

Verified by Experts

The correct Answer is:
a
Given lines are
`(x-5)/(3)=(y-7)/(-1)=(z+2)/(1)=r_(1)" "("say")`
and `(x+3)/(-36)=(y-3)/(2)=(z-6)/(4)=r_(2)" "("say")`
`becausex=3r_(1)+5=-36r_(2)-3,y=-r_(1)+7=3+2r_(2)`
and `z=r_(1)-2=4r_(2)+6`
On solving, we get
`x=12,y=(5)/(3),z=(10)/(3)`
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