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The equation of the plane which passes...

The equation of the plane which passes through the line of intersection of planes ` vec rdot vec n_1=, q_1, vec rdot vec n_2=q_2` and the is parallel to the line of intersection of planers ` vec rdot vec n_3=q_3a n d vec rdot vec n_4-q_4` is

A

`[vecn_(2)vecn_(3)vecn_(4)](vecr.vecn_(1)-q_(1))=[vecn_(1)vecn_(3)vecn_(4)](vecr.vecn_(2)-q_(2))`

B

`[vecn_(1)vecn_(2)vecn_(3)](vecr.vecn_(4)-q_(4))=[vecn_(4)vecn_(3)vecn_(1)](vecr.vecn_(2)-q_(2))`

C

`[vecn_(4)vecn_(3)vecn_(1)](vecr.vecn_(4)-q_(4))=[vecn_(1)vecn_(2)vecn_(3)](vecr.vecn_(2)-q_(2))`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
a

`vecr*vec(n_(1))+lamdavecr*vec(n_(2))= q_(1)+ lamdaq_(2)" "` (i)
where `lamda` is a parameter.
So `vec(n_(1))+ lamda vec(n_2)` is normal to plane (i). Now, any plane parallel to the line of intersection of the planes `vecr`.
`vec(n_3)= q_(3) and vecr*vec(n_(4)) = q_(4)` is of form `vecr*(vec(n_(3))xxvec(n_(4)))=d`. Hence, we must have
`" "[vec(n_1)+lamdavec(n_2)]*[vec(n_3)xxvec(n_4)]=0`
or `" "[vec(n_1)vec(n_3)vec(n_4)] + lamda[vec(n_2)vec(n_3)vec(n_4)]=0`
or `" " lamda = (-[vec(n_1)vec(n_2)vec(n_4)])/([vec(n_1)vec(n_3)vec(n_4)] )`
On putting this value in Eq. (i), we have the equation of the required plane as
`" "vecr*vec(n_1)-q_1= ([vec(n_1)vec(n_3)vec(n_4)])/([vec(n_2)vec(n_3)vec(n_4)])(r*vec(n_2)-q_2)`
or `" "[vec(n_2) vec(n_3)vec(n_4)](vecr*vec(n_1)-q_1)`
`" "=[vec(n_1)vec(n_3)vec(n_4)] (vecr*vec(n_2) - q_2) `
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