Consider the following sets: A = set all rectangles in the same plane B = set all squares in the same plane C = set all parellegrams in the same plane Find the following sets : `(i) A-B (ii) C-A (iii) A cap C (iv) B cap C (v) B cup C (Vi ) A cap B cup C `
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We have A = set all rectangles in the same plane B = set all squares in the same plane C = set all parellegrams in the same plane. Since all squares are rectangels `B sube A.` Also all squares and rectagles are pareallelograms . `So A, B sube C ` `therefore B sube A sube C` (i) A - B= set of all rectangle which are not squares (ii) C- A = set of all parallelograms which are not rectangles of squares = set of all parallelograms which are not rectangles of squares (iii) `A cap C`= set of all rectangles= A (iv) `B cap C= `set of all squares = B ( v) `B cup C` = set of all parallelograms = C (vi ) `A cap B cap `= set of all squares = B
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