`|(x-3)/(x+1)| le 1` or `-1 le (x-3)/(x+1) le 1` `rArr (x-3)/(x+1)-1 le 0 " and " 0 le (x-3)/(x+1)+1` `rArr (-4)/(x+1) le 0 " and " 0 le (2x -2)/(x+1)` `rArr x lt -1 " and " { x lt - 1 or x ge 1}` `rArr x ge 1`
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