Let `a >2`
be a constant. If there are just 18 positive integers satisfying the
inequality `(x-a)(x-2a)(x-a^2)<0,`
then find the value of `adot`
Text Solution
Verified by Experts
As `a gt 2` Hence `a^2 gt 2a gt a gt 2 ` Hence , the solution set is as follows : Between (0,a) ther are (a-1) positive interger between `(2a ,a ^2) ` there are `a^2- 2a -1 ` itnergers ,.Therefore `a^2-2a-1+a-1=18` or `a^2-a-20=0` or `(a-5)(a+4)=0` `rArr a=5`
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