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Evaluate: ("lim")(nvecoo)n^(-n^2){(n+2^0...

Evaluate: `("lim")_(nvecoo)n^(-n^2){(n+2^0)(n+2^(-1))(n+2^(-2))(n+2^(-n+1))}^n`

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We have `underset(ntooo)limn^(-n^(2))[(n+1)(n+(1)/(2))...(n+(1)/(2^(n-1)))]^(n)`
`=underset(ntooo)lim[((n+1)(n+(1)/(2))...(n+(1)/(2^(n-1))))/(n^(n))]^(n)`
`=underset(ntooo)lim((n+1)/(n))^(n).((n+(1)/(2))/(n))^(n)...((n+(1)/(2^(n-1)))/(n))^(n)`
`=underset(ntooo)lim(1+(1)/(n))^(n).(1+(1)/(2n))^((2n)/(2))...(1+(1)/(2^(n-1)n))^((2^(n-1).n)/(2^(n-1)))`
`=underset(ntooo)lime^(1).e^((1)/(2)).e^(2^((1)/(2)))...e^((1)/(2^(n-1)))`
`=e^(1).e^((1)/(2)).e^(2^((1)/(2)))...("infinite factors")`
`=e^((1)/(1-(1)/(2)))=e^(2)`
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CENGAGE-LIMITS-Question Bank
  1. Evaluate: ("lim")(nvecoo)n^(-n^2){(n+2^0)(n+2^(-1))(n+2^(-2))(n+2^(-n+...

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  2. If Lim(x rarr 0) (1-cosx)/(e^(ax)-bx-1) exist and is equal to 1, then ...

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  3. If graph of a function f(x) is shown in the adjacent figure, then Lim(...

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  4. Let f(x) =(sec x)^(cosecx) + (cot x)^(sin x). Then the value of Lim(x ...

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  5. Lim(z rarr 0){{max((sin^(-1)x + cos^(-1)x)^(2), min(x^(2)+4x+7))}. (si...

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  6. The reciprocal of the value of: ("lim")(ntooo)(1-1/(2^2))(1-1/(3^2))(1...

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  7. The value of Lim(x rarr 0)(sum(k =1)^(2016){(sinx)/x+2015k})/2016 is [...

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  8. Lim(x rarr oo) (30+4sqrtx+7root(3)(x))/(2+sqrt(4x-7)+root(3)(6x-2) )eq...

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  9. If Lim(x rarr0) ((a sin x + b tan x)/x^(3))= 3/2 then |a+2b| is equal ...

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  10. lim(n rarr 0)(1/(1+n^(2))+2/(1+n^(2))+3/(1+n^(2))+....+n/(1+n^(2))) is...

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  11. Find the value of lim(n rarr oo)sum(k=1)^(n)(k^(2)+k-1)/((k+1)!) .

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  12. The value of Lim(x rarr 0)((tanx)^(1/x)+(1+sinx)^(x)) where x gt0 is e...

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  13. If Lim(x rarr 0) (a sinx + bxe^(x)+3x^(2))/(sin x-2x+tanx) exists and ...

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  14. If Lim(x rarr a) (sqrt(x-b)-sqrt(a-b))/(x^(2)-a^(2))(a gt b) = 1/64 an...

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  15. If lim(x rarr 0) (k+cos lx)/x^(2)exists and has the value equal to -4 ...

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  16. Lim(x rarr 0)((3sin x- sin 3x)^(4))/((sec x - cosx)^(6)) is equal to

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  17. Lim(x rarr 0)(tanx sqrt (tanx)-sin x sqrt(sinx))/(x^(3).sqrtx) equals

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  18. f(x)=("ln"(x^(2)+e^(x)))/("ln"(x^(4)+e^(2x)))." Then "underset(xtooo)l...

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