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Find the angle between the asymptotes of...

Find the angle between the asymptotes of the hyperbola `(x^2)/(16)-(y^2)/9=1` .

Text Solution

Verified by Experts

The correct Answer is:
`tan^(-1)(24)/(7)`
The angle between the asymptotes is given by
`tan^(-1)((2ab)/(a^(2)-b^(2)))=tan^(-1){(2(4)(3))/(16-9)}`
`=tan^(-1)((24)/(7))`
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