Draw the graph of `y=cos^(-1){x}," where "{*}" represetns the fractional part function"`.

Explanation

We have `y=sin^(-1){x}`
`{x}in[0,1)AAx inR.`
Here the domain of the function is R.
`0le{x}lt1`
`therefore" "0lesin^(-1){x}ltpi//2`
So the range of `y=f(x)" is "[0, pi//2)`.
Now y = f(x) is periodic and has period 'I'.
Also for `0lexlt1, {x}=xthereforey=sin^(-1){x}=sin^(-1)x`
Graphs of y = {x} =x and `y = sin^(-1) {x}= sin^(-1)x" and "y = sin^(-1)x" for "x in [0,1)` are shown in the adjecent figure.
Since the perios of y y =f(x) is 'I', the graph of the function can be drawn by repetitoon of the above graph for each interval `(n, n+1), n in Z`