The probability that a bulb produced by a factory will fuse after 150 days if used is 0.05. what is the probability that out of 5 such bulbs none will fuse after 150 days of use? a.`1-(19/20)^5` b. `(19/20)^5` c. `(3/4)^5` d. `90(1/4)^5`

Options

A. `1-(19//20)^(5)`
B. `(19//20)^(5)`
C. `(3//4)^(5)`
D. `90(1//4)^(5)`

Answer

B

Explanation

Here `p=19//20,q=1//20,n=5,r=5.` The required probability is
`=""^(5)C_(3)((19)/(20))^(5)((1)/(20))^(0)=((19)/(20))^(5)`