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Find the equation of the tangent to the parabola `y^2=8x` having slope 2 and also find the point of contact.

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The equation of the tnagent to `y^(2)=4ax` having slope m is `y=mx+(a)/(m)`
Hence, for the given parabola, the equation of the tangent is
`y=2x+(2)/(2)ory=2x+1`
and the point of contact is
`((a)/(m^(2)),(2a)/(m))-=((2)/(2^(2)),(2(2))/(2))-=((1)/(2),2)`
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