"If " int(5tanx)/(tanx-2)dx=x+a " In"(si...

`"If " int(5tanx)/(tanx-2)dx=x+a " In"(sinx-2cosx)+k " then " a= `

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The correct Answer is:

` int(5tanx)/(tanx-2)dx=int(5sinx)/(sinx-2cosx)dx`
`=int((sinx-2cosx)+2(cosx+2sinx))/((sinx-2cosx))dx`
`=int dx+2int(cosx+2sinx)/(sinx-2cosx)dx`
`=x+2 " In"|(sinx-2cosx)|+k`

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int(sqrt(tanx))/(sin2x)dx is

`sqrt(tanx)+c`

`2sqrt(tanx)+c`

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inte^(x)secx(1+tanx)dx equals

`e^(x)cosx+C`

`e^(x)secx+C`

`e^(x)sinx+C`

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`"If " int(5tanx)/(tanx-2)dx=x+a " In"(sinx-2cosx)+k " then " a= `

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int(sqrt(tanx))/(sin2x)dx is

inte^(x)secx(1+tanx)dx equals

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