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If `H` is the othrocenter of an acute angled triangle ABC whose circumcircle is `x^2+y^2=16 ,` then circumdiameter of the triangle HBC is (a)1 (b) 2 (c) 4 (d) 8

A

1

B

2

C

4

D

8

Text Solution

Verified by Experts

The correct Answer is:
D
Circumdiameter of `DeltaHBC`
`= (a)/(sin angleBHC) = (a)/(sin A) = 2R = 8`
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