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Find in degrees the angle subtended at t...

Find in degrees the angle subtended at the centre of a circle of diameter 50cm by an arc of length 11cm.

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Here, `r=25cm" and "s=11 cm`. Therefore,`theta=(s/r)^R`
or `theta=(11/25)^R=(11/25xx182/pi)^(@)=(11/25xx180/22xx7)^(@)`
`=(126/5)^(@)=25 1/5)^(@)=25^(@)(1/5xx60)=25^(@)12'`
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CENGAGE-TRIGONOMETRIC FUNCTIONS -SINGLE CORRECT ANSWER TYPE
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