Let P = [theta : sintheta – costheta = s...

Let `P = [theta : sintheta – costheta = sqrt2 costheta) andQ= {theta : sintheta + costheta = sqrt2 sintheta}` be two sets. Then:

`psubQ and Q-P=phi`

`QcancelsubP`

`PcancelsubQ`

P=Q

Verified by Experts

The correct Answer is:

In set P, `sintheta=(sqrt2+1)costheta`
`or tantheta=sqrt2+1`
In set Q, `(sqrt2-1)sintheta=costheta`
`or tan thetaa=1/(sqrt2-1)=sqrt2+1`
`rArr P=Q`

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If sintheta +costheta =1 then sin^6 theta +cos^6 theta is:

-1