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If the equation 4x^2-x-1=0a n d3x^2+(lam...

If the equation `4x^2-x-1=0a n d3x^2+(lambda+mu)x+lambda-mu=0` have a root common, then the rational values of `lambdaa n dmu` are a.`lambda=(-3)/4` b. `lambda=0` c. `mu=3/4` b.`mu=0`

A

`lambda=0`, `mu=(-3)/(4)`

B

`lambda=(-3)/(4)`, `mu=(3)/(4)`

C

`lambda=(-3)/(4)`, `mu=0`

D

`lambda=(-3)/(4)`, `mu=(1)/(4)`

Text Solution

Verified by Experts

The correct Answer is:
C

`(c )` Roots of `4x^(2)-x-1=0` are irrational.
So, one root common implies both roots are common.
`:. (4)/(3)=(-1)/(lambda+mu)=(-1)/(lambda-mu)=(-2)/(2lambda)=(0)/(2mu)`
So, `lambda=(-3)/(4)`, `mu=0`
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