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Solve |sinx +cos x |=|sinx|+|cosx|, x in...

Solve `|sinx +cos x |=|sinx|+|cosx|, x in [0,2pi]`.

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The given relation holds only when sin x and cos x have the same sign or at least one of them is zero.
Hence, `x in [ 0, pi//2] cup [pi,3pi//2] cup {2pi}.`
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