Home
Class 12
MATHS
Let [x] denotes the greatest integer les...

Let `[x]` denotes the greatest integer less than or equal to `x` . If the function `f(x)="tan"(sqrt([n])x)` has period `pi/3dot` then find the value of `ndot`

Text Solution

Verified by Experts

The correct Answer is:
[9, 10)
Clearly, `f(x) =tan(sqrt([n])x)` has period `(pi)/(sqrt([n])).`
But it is given that `tan(sqrt([n])x)` has period `(pi)/(3)`. Therefore,
`(pi)/(sqrt([n]))=(pi)/(3)`
or `[n] =9 " or " n in [9,10).`
Promotional Banner

Topper's Solved these Questions

  • RELATIONS AND FUNCTIONS

    CENGAGE|Exercise Exercise 1.12|9 Videos

  • RELATIONS AND FUNCTIONS

    CENGAGE|Exercise Exercise 1.13|7 Videos

  • RELATIONS AND FUNCTIONS

    CENGAGE|Exercise Exercise 1.10|6 Videos

  • Quadratic Equations, Inequalities, Modulus and Logarithms

    CENGAGE|Exercise Question Bank|28 Videos

  • SCALER TRIPLE PRODUCTS

    CENGAGE|Exercise DPP 2.3|11 Videos

Similar Questions

Explore conceptually related problems

Let [x] denotes the greatest integer less than or equal to x. If f(x) =[x sin pi x] , then f(x) is

Let [x] denote the greatest integer less than or equal to x . If x = (sqrt(3) +1)^(5) , then [x] is equal to

If [x] denotes the greatest integer less than or equal to x , then find the value of the integral int_0^2x^2[x]dxdot

For a real number y, let [y] denotes the greatest integer less than or equal to y. Then, the function f(x) = (tan pi[(x -pi)])/(1+[2]^(2)) is

Let f(x) = (x^2-9x+20)/(x-[x]) where [x] denotes greatest integer less than or equal to x ), then

let f(x)=(sin4pi[x])/(1+[x]^(2)) , where px] is the greatest integer less than or equal to x then

If [x] denotes the greatest integer less than or equal to x , then evaluate ("lim")_(ntooo)1/(n^2)([1.x]+[2.x]+[3.x]+....+[n.x])

If [.] denotes the greatest integer less than or equal to the ral number under consideration, and -1lt=x a. [x] b. [y] c. [z] d. none of these

For each x in R , let [x]be the greatest integer less than or equal to x. Then lim_(xto1^+) (x([x]+absx)sin[x])/absx is equal to

Let f (x) = [x] , where [x] denotes the greater integer less than or equal to x. if a = sqrt(2011 ^2 +2012 ) then the value of f (a) is equal to