If `f(x)={xcosx+(log)_e((1-x)/(1+x))a; x=0; x!=0` is odd, then `a_______,`

Answer

0

Explanation

For `x ne 0, f(x)=x cosx + log_(e)((1-x)/(1+x))`
` :. f(-x)=(-x)cos(-x)+log_(e)((1+x)/(1-x))`
`= -x cosx-log_(e)((1-x)/(1+x))`
`= -f(x)`
For `x=0`, we must have `f(-x)= -f(x)`
` :. a= -a`
` :. a=0`