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If the eccentric angles of two points P and Q on the ellipse `x^2/28+y^2/7=1` whose centre is C differ by a right angle then the area of `Delta CPQ` is

A

5

B

6

C

7

D

8

Text Solution

Verified by Experts

The correct Answer is:
C
If P is the point `(a cos theta, b sin theta)`, the coordinates of Q are `(a cos (theta+ (pi)/(2)), b sin (theta + (pi)/(2)))`
i.e., `(-a sin theta, b cos theta)` where `a^(2) = 28, b^(2) =7`

`:.` The area of `Delta CPQ = (1)/(2) |ab cos^(2) theta + ab sin^(2) theta| { :' area = |{(1)/(2)(x_(1)y_(2)-x_(2)y_(2))}|}`
`= (1)/(2)ab`
`= (1)/(2) (sqrt(28)) (sqrt(7)) =7` sq units.
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