Home
Class 12
MATHS
An ellipse passes through the point (2,3...

An ellipse passes through the point (2,3) and its axes along the coordinate axes, `3x +2y -1 = 0` is a tangent to the ellipse, then the equation of the ellipse is`

A

`(x^(2))/(4)+4y^(2) =1`

B

`(x^(2))/(8)+(y^(2))/(1)=1`

C

`4x^(2) +(y^(2))/(4) =1`

D

No such ellipse exists

Text Solution

Verified by Experts

The correct Answer is:
D


From the position of line and point, it is clear that no such ellipse exists.
Promotional Banner

Topper's Solved these Questions

  • ELLIPSE

    CENGAGE|Exercise Multiple Correct Answers Type|6 Videos
  • DOT PRODUCT

    CENGAGE|Exercise DPP 2.1|15 Videos
  • ELLIPSE AND HYPERBOLA

    CENGAGE|Exercise Question Bank|1 Videos

Similar Questions

Explore conceptually related problems

If 4x+y+k=0 is a tangent to the ellipse x^(2)+3y^(2)=3 then k = ?

An ellipse passes through the point (4,-1) and touches the line x+4y-10=0 . Find its equation if its axes coincide with the coordinate axes.

An ellipse passes through the point (4,-1) and touches the line x+4y-10=0 . Find its equation if its axes coincide with the coordinate axes.

The eccentricity of an ellipse with its centre at the origin is 1/2 . If one of the directices is x = 4 , then the equation of the ellipse is

Let S=(3,4) and S'=(9,12) be two foci of an ellipse. If the coordinates of the foot of the perpendicular from focus S to a tangent of the ellipse is (1, -4) then the eccentricity of the ellipse is

An ellipse intersects the hyperbola 2x^2-2y^2 =1 orthogonally. The eccentricity of the ellipse is reciprocal to that of the hyperbola. If the axes of the ellipse are along the coordinate axes, then (a) equation of ellipse is x^2+ 2y^2 =2 (b) the foci of ellipse are (+-1, 0) (c) equation of ellipse is (x^2 +2y=4) (d) the foci of ellipse are (+-2, 0)

An ellipse is sliding along the coordinate axes. If the foci of the ellipse are (1, 1) and (3, 3), then the area of the director circle of the ellipse (in square units) is (a) 2pi (b) 4pi (c) 6pi (d) 8pi

An ellipse is drawn by taking a diameter of the circle (x""""1)^2+""y^2=""1 as its semiminor axis and a diameter of the circle x^2+""(y""""2)^2=""4 as its semi-major axis. If the centre of the ellipse is the origin and its axes are the coordinate axes, then the equation of the ellipse is (1) 4x^2+""y^2=""4 (2) x^2+""4y^2=""8 (3) 4x^2+""y^2=""8 (4) x^2+""4y^2=""16

The ellipse x^2+""4y^2=""4 is inscribed in a rectangle aligned with the coordinate axes, which in turn is inscribed in another ellipse that passes through the point (4, 0). Then the equation of the ellipse is (1) x^2+""16 y^2=""16 (2) x^2+""12 y^2=""16 (3) 4x^2+""48 y^2=""48 (4) 4x^2+""64 y^2=""48

If a circle passes through the points where the lines 3kx- 2y-1 = 0 and 4x-3y + 2 = 0 meet the coordinate axes then k=