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The correct Answer is:
`2 sqrt(3) `sq. unit
Equation of tangent to circle `x^(2)+y^(2)=4` at point `P(1,sqrt(3))` is `1.x+sqrt(3).y=4,i.e., x +sqrt(3)y =4`.
It meets x-axis at A(4,0) .

`:. ` Area of triangle `OAP =(1)/(2)OA xx PM`
`=(1)/(2) 4 xxsqrt(3)=2 sqrt(3)`
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