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Options

A. `y=sqrt(3)x+4`
B. `sqrt(3)y=x+4`
C. `y=sqrt(3)x-4`
D. `sqrt(3)y=x-4`

Answer

2,4

Explanation

Clearly, A -= ( -2 cos 60^(@),2 sin 60^(@))`
and `B -= (2 cos 60^(@), -2 sin 60^(@))`
The tangent at A is `x( -2 cos 60^(@)) +y(2 sin 60^(@)) = 4` and that at B is `x (2 cos 60^(@)) + y(-2 sin 60^(@)) = 4`.