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If sin A+cos2A=1//2 and cos A+sin2A=1//3...

If `sin A+cos2A=1//2` and `cos A+sin2A=1//3`. Then find the value of `sin 3A`.

Text Solution

Verified by Experts

The correct Answer is:
`-59//72`
Squaring and adding, we get
`1+1+2sinA cos 2A+2 cos A sin 2A`
`=(1//4)+(1//9)=(13//36)`
`rArr sin 3A=-59//72`
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