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If A+B=225^(@), then find the value of (...

If `A+B=225^(@)`, then find the value of `(cotA)/(1+cotA)xx(cot B)/(1+cotB)`

Text Solution

Verified by Experts

The correct Answer is:
`1//2`
`(cotA)/(1+cotA)xx(cotB)/(1+cotB)`
`=(1)/((1+tanA)(1+tanB))`
`=(1)/(tan A+tan B+1+tan A tan B)`
Now, `tan(A+B)=tan225^(@)`
`rArr tanA+tanB=1-tan A tan B`
Hence, from Eq. i,
RHS`=(1)/(1-tan A tan B+1+tan A tan B)=(1)/(2)`
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  • In triangle ABC the value of ( cot A/2 cot ""B/2 -1)/( cot""A/2 cot""B/2) is

    A
    `(a)/( a+b+c)`
    B
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    C
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    D
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