If sin x+siny+sinz=0=cosx+cosy+cosz, the...

If `sin x+siny+sinz=0=cosx+cosy+cosz`, then find the value of `cos(theta-x)+cos(theta-z)`

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Verified by Experts

The correct Answer is:

0

`cos(theta-x)+cos(theta-y)+cos(theta-2)`
`=cos theta(sumcosx)+sin(sum sin)=0`

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