Find the value of `theta` which satisfy `rsintheta=3a n dr=44(1+sintheta),0lt=thetalt=2pidot`

Explanation

We have
`r sin theta =3` and `r=4 (1+ sin theta)`
Eliminating r, we get
`4 sin^(2) theta +4 sin theta -3 =0`
`:. (2 sin theta-1) (2 sin theta +3)=0`
`rArr sin theta =1/2, -3/2` (not possible)
`rArr theta=pi/6, (5 pi)/6`
Thus, we have two solutions.