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Solve sin^(2) theta-cos theta=1/4, 0 le ...

Solve `sin^(2) theta-cos theta=1/4, 0 le theta le 2pi`.

Text Solution

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The correct Answer is:
`theta=pi/3, (5 pi)/3`

`sin^(2) theta - cos theta=1/4`
or `1-cos^(2) theta - cos theta=1/4`
or `4 cos^(2) theta+4 cos theta -3=0`
or `(2 cos theta+3) (2 cos theta-1)=0`
or `cos theta=1/2, -3/2` (rejected)
`rArr theta = pi//3, (5pi)/3` in the given interval
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