Find the number of solution of `[cosx]+|sinx=1inpilt=xlt=3pi`
(where `[]`
denotes the greatest integer function).
Text Solution
Verified by Experts
We have `[cos x]+|sin x|=1` Now, `-1 le cos x le 1` `:.` Possible values of `[cos x]` are `0, 1, -1` Case I : `[cos x]=-1` or `cos x in [-1, 0)` `:. -1 +|sin x|=1` `rArr |sin x|=2` (not possible) Case II : `[cos x]=0` or `cos x in [0, 1)` `:. |sin x|=1` `rArr x=(3pi)/2, (5pi)/2` Case III : `[cos x]=1` or `cos x=1` `:. |sin x|=0` `:. x=2pi` Hence, there are three solutions.
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