We have `(tan 3x-tan 2x)/(1+tan 3x tan 2x)=1` `rArr tan (3x-2x)=1` or `tan x=1` One of the principal solution of the equation is `x=pi/4`. Since period of `tan x` is `pi`, general solution is given by `x=npi+pi/4, n in Z`. But for these values of x, term `(tan 2x)` in original equation is not defined. So, `x=n pi+pi/4, n in Z` is not the solution of the equation.
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