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let N =(log(3) 135/log(15) 3) - (log(3) ...

let `N =(log_(3) 135/log_(15) 3) - (log_(3) 5/log_(405) 3)`

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
C
`(log_(3)135)/(log_(15)3)-(log_(3)5)/(log_(405)3)`
`=(3+log_(3)5)(1+log_(3)5)-log_(3)5 log_(3)405`
`= (3+log_(3)5)(1+log_(3)5)-log_(3)5 log_(3)(81xx5)`
`=(3+log_(3)5)(1+log_(3)5)-log_(3)5(4+log_(3)5)`
= 3
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