1/log(ab)(abc)+1/log(bc)(abc)+1/log(ca)(...

`1/log_(ab)(abc)+1/log_(bc)(abc)+1/log_(ca)(abc)` is equal to:

A

`1//2`

B

1

C

2

D

4

Verified by Experts

The correct Answer is:

C

`(1)/(log_(bc)abc)+(1)/(log_(ca)abc)+(1)/(log_(ab)abc)`
`=log_(abc)bc+log_(abc)ca+log_(abc)ab`
`log_(abc)a^(2)b^(2)c^(2)=2`

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