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If in a Delta ABC ,tanA+tanB+tanC=6, the...

If in a `Delta ABC ,tanA+tanB+tanC=6,` then `cotA cotB cotC=`

A

`1/6`

B

1

C

6

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
`tan A+tan B+tn C`
= tna A tan B tna C = 6
`therefore cot A cot B cot C = 1//6`
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