Solve the equation `4^(x)- 5 xx2^(x) + 4 = 0.`

Explanation

We have,
`4^(x)- 5 xx2^(x) + 4 = 0.`
or `(2(^x))^(2) - 5 (2^(2))+ 4 = 0 `
`rArr y^(2)- 5y + 4 = 0,` Where `y = 2^(2)`
or ` (y - 4) (y- 1) = 0`
or y = 1, 4
`rArr 2^(x) = 1 2^(0), 2^(x) = 2^(2)`
`rArr x` = 0, 2
Hence, the roots of the given equation are 0 and 2.