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The correct Answer is:
9
Given `s_1/S_11=6/11`
`rArr (7/2[2a+6d])/(11/2[2a+10d])=6/11`
`rArr (7(a+3d))/(11(a+5d))=6/11`
`rArr 7a+21d= 6a+30d `
`rArr a = 9d`
`rArr T_7=a+6d=15d`
Given `130 lt 15 d lt 140`
`rArr d=9`
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