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Let D1=|a b a+b c d c+d a b a-b|a n dD2=...

Let `D_1=|a b a+b c d c+d a b a-b|a n dD_2=|a c a+c b d b+d a c a+b+c|` then the value of `|(D_1)/(D_2)|,w h e r eb!=0a n da d!=b c ,` is _____.

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The correct Answer is:
2
Using `C_(3) to C_(3) -(C_(1)+C_(2))" in " D_(1) " and" D_(2) ` we have
`(D_(1))/(D_(2)) =(-2b(ad-bc))/(b(ad-bc)) =-2`
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