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Let f(x)=int(dx)/(e^(x)+8e^(-x)+4e^(-3x)...

Let `f(x)=int(dx)/(e^(x)+8e^(-x)+4e^(-3x)),g(x)=int(dx)/(e^(3x)+8e^(x)+4e^(-x)).`
`int(f(x)-2g(x))dx`

A

`(1)/(2)log|(e^(x)+2e^(-x)-2)/(e^(x)+2e^(-x)+2)|+C`

B

`(1)/(4sqrt3)log|(e^(x)-2e^(-x)-2sqrt3)/(e^(x)+2e^(-x)+2sqrt3)|+C`

C

`(1)/(2sqrt3)tan^(-1)((e^(x)-2e^(-x))/(2sqrt3))+C`

D

`(1)/(2)tan^(-1)((e^(x)+2e^(-x))/(2))+C`

Text Solution

Verified by Experts

The correct Answer is:
D
`int(f(x)-2g(x))dx`
`=int(e^(x)(e^(2x)-2))/(e^(4x)+8x^(2x)+4)dx` put `e^(x)=t`
`=int(1-(2)/(t^(2)))/((t+(2)/(t))^(2)+4)dt=(1)/(2)tan^(-1)((t+(2)/(t))/(2))+C`
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Knowledge Check

  • int (dx)/(e^(x)-1) is

    A
    `log |e^(x)| -log | e^(x) -1| +c `
    B
    `log |e^(x) | + log | e^(x) -1|+c `
    C
    log | `e^(x) -1| -log |e^(x) | +c `
    D
    log `|e^(x)+1|-log|e^(x)|+c`

  • int(dx)/(e^(x)+e^(-x)) is equal to

    A
    `tan^(-1)(e^(x))+C`
    B
    `tan^(-1)(e^(-x))+C`
    C
    `log(e^(x)-e^(-x))+C`
    D
    `log(e^(x)+x^(x))+C`

  • int(e^(x)+1)/(e^(x))dx :

    A
    `x-e^(-x)+c`
    B
    `x+e^(-x)+c`
    C
    `x+c`
    D
    `e^(x)+c`

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    int(1)/(e^(x))dx=………..

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