The e.m.f of the following Daniell cell at 298K is E_1 . Zn|ZnSO_4(0.01M)||CuSO_4(1.0)|Cu When concentration of ZnSO_4 is 1.0 M and that of CuSO_4 is 0.01M, if e.m.f changed to E_2 . What is the relationship between E_1 and E_2 ?
In a galvanic cell,
Define galvanic cell.
The e.m.f of the cell Cu|Cu^(2+)(aq)||Ag^(+)(aq)|Ag is 0.46V. The e.m.f for the following cell reaciton: 3Cu+6Ag^+ (aq)rarr3Cu^(2+)+6Ag is 0.46y V. The value of y is
Calculate the e.m.f. of the following cell at 298 K, M g ∣ ∣ M g 2 + ( 0.130 M ) ∣ ∣ ∣ ∣ A g + ( 1.0 × 10 − 4 M ) ∣ ∣ A g
Calculate the e.m.f. of the following cell at 298 K, Mg|Mg^(2+)(0.130M)||Ag^(+)(1.0xx10^(-4)M)|Ag
Calculate the e.m.f. of the following cell at 298 K. Mg_((s))|Mg^(2+)(0.001M)||Cu^(2+)(0.0001M)|Cu_((s)) Given E^(@)(Cu^(2+)|Cu)=0.34V and E^(@)(Mg^(+)|Mg)=-2.37V .
If the e.m.f of a galvanic cell is neagative, it implies that:
Why does the e.m.f. of a galvanic cell decrease on drawing current from it? When does it fall to zero
