Use the following standard electrode potentials, calculate `DeltaG^(@)` in kJ`//`mol for the indicated reaction : `5Ce^(4+)(aq)+Mn^(2+)(aq)+4H_(2)O(l)to5Ce^(3+)(aq)+
MnO_(4)^(-)(aq)+8H^(+)(aq)` `MnO_(4)^(-)(aq)+8H^(+)(aq)+5e^(-)toMn^(2+)(aq)+4H_(2)O(l), E^(@)=+1.51 V` `Ce^(4+)(aq)+e^(=)toCe^(3+)(aq)" "E^(@)=+1.61 V`
A
`-9.65`
B
`-24.3`
C
`-48.25`
D
`-35.2`
Text Solution
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The correct Answer is:
C
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