calculate the value of equilibrium constant `(K_f)` for the reaction: `Zn^(2+)(aq)+4OH^(-)(aq)iffZn(OH)_4^(2-)(aq)` Given: `Zn^(2+)(aq)+2e^(-)toZn(s0,E^(@)=-0.76 V` `Zn(OH)_4^(2-)(aq)+2e^(-)toZn(s)+4OH^(-)(aq),E^(@)=-1.36 V` `2.303(RT)/F=0.06`
A
`10^10`
B
`2xx10^10`
C
`10^20`
D
None of these
Text Solution
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The correct Answer is:
C
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