A 20.0 mL sample of a 0.20 M solution of the weak diprotic acid H_(2)A is titrated with 0.250 M NaOH. The concentration of solution at the second equivalent point is:
20 mL of 0.2 M NaOH(aq) solution is mixed with 35 mL of this 0.1 ML NaOH (aq) solution and the resultant solution is diluted to 100 mL. 40 mL of this diluted solution reacted with 10% impure sample of oxalic acid (H_(2)C_(2)O_(4)) The mass of impure is:
When 100mL solution of NaOH and NaCO_(3) was first titrated with N/10 HCl in presence of HPh, 17.5mL were usedtill end point is obtained. After this end point MeOH was added and 2.5mL of same HCl were required to attain new end point. The amount NaOH in mixture is:
A solution of weak acid HA was titrated with base NaOH. The equivalent point was reached when 40 mL. Of 0.1 M NaOH has been added. Now 20 mL of 0.1 M HCl were added to titrated solution, the pH was found to be 5.0 What will be the pH of the solution obtained by mixing 20 mL of 0.2 M NaOH and 20 mL of 0.2 M HA?
The bromination of acetone that occurs in acid solution is represented by the equation CH_3COCH_3(aq) + Br_3(aq) rarr CH_3COCH_2Br(aq) + H^(+)(aq) + Br^(-)(aq) These kinetic data were obtained for given reaction concentrations. Based on these data, the rate of reaction is :
A colloidal solution of Agl is prepared by the following two methods : (a) Adding AgNO_3 to KI (aq) solution (b) Adding KI to AgNO_3 (aq) solution. Give reasons for the origin of charges.
0.1 M formic acid solution is titrated against 0.1 M NaOH solution. What would be the difference in pH between 1/5 and 4/5 stages of neutralization of acid?
The 25mL of a 0.15 M solution of lead nitrate, Pb(NO_3)_2 reacts with all of the aluminium sulphate, Al_2 (SO_4)_3 , present in 20 mL of a solution. What is the molar concentration of the AI_2(SO_4)_3 + 3Pb(NO_3)_2(aq)+AI_2(SO_4)_3(aq)rarr3PbSO_4(s)+2AI(NO_3)_3(aq)
When a 20 mL of 0.08 M weak base BOH is titrated with 0.08 M HCl, the pH of the solution at the end point is 5. What will be the pOH if 10 mL of 0.04 M NaOH is added to the resulting solution? [Given : log 2=0.30 and log 3=0.48]
