Home
Class 11
CHEMISTRY
The molar conductivity of 0.04 M solutio...

The molar conductivity of 0.04 M solution of `MgCl_2` is 200 `Scm^2mol^(-1)` at 298 k. A cell with electrodes that are 2.0`cm^2` in surface area and 0.50cm apart is filled with `MgCl_2` solution.
Conductance of `MgCl_2` solution is :

A

`8xx10^(-3)`S

B

32S

C

0.032S

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    NARENDRA AWASTHI|Exercise Level 3 - One Or More Answers Are Correct|3 Videos
  • ELECTROCHEMISTRY

    NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
  • ELECTROCHEMISTRY

    NARENDRA AWASTHI|Exercise Level 2|2 Videos
  • DILUTE SOLUTION

    NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
  • GASEOUS STATE

    NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|1 Videos

Similar Questions

Explore conceptually related problems

The molar conductivity of 0.04 M solution of MgCl_2 is 200 Scm^3mol^(-1) at 298 k. A cell with electrodes that are 2.0 cm^2 in surface area and 0.50cm apart is filled with MgCl_2 solution How much current will flow when the potential difference between the two electrodes is 5.0V?

Solution of x^2 +2 =0 is:

The conductivity of 0.20 MKCl solution at 298 K is 0.0248 S cm^-1 . Calculate its molar conductivity.

What is the molarity of 0.2N Na_2CO_3 solution ?

The conductivity of 0.35M NaCl solution at 298K is 0.025 S/cm. Calculate its molar conductivity .

The molar conductivity of 1.5 M solution of an electrolysis is found to be 138.9 S cm^2 mol^-1 . Calculate the conductivity of this solution?

The molar conductivity of a 0.5 mol/dm3 solution of AgNO3 with electrolytic conductivity of 5.76 x 10-3 S cm-1 at 298 K is

The conductivity of 0.1 n NaOH solution is 0.022 S cm^(-1) .When equal volume of 0.1 N HCl solution is added, the conductivity of resultant solution is decreased to 0.0055 S cm^(-1) . The equivalent conductivity of NaCl solution is :

Molar conductivity of a solution of an electrolyte AB_3 is 150 Scm^2mol^(-1) . If it ionises as AB_(3)toA^(3+)+3B^(-) , its equivalent conductivity will be :