The resistance of a conductivity cell containing 0.001M KCl solution at 298K is 1500`Omega`. What is the cell constant ( in `mm^(-1)`) if the conductivity of 0.001M KCl solution is `2xx10^(-3)Smm^(-1)`
Text Solution
Verified by Experts
The correct Answer is:
C
Topper's Solved these Questions
ELECTROCHEMISTRY
NARENDRA AWASTHI|Exercise Level 1 (Q.1 To Q.30)|1 Videos
ELECTROCHEMISTRY
NARENDRA AWASTHI|Exercise Level 1 (Q.91 To Q.120)|1 Videos
DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
The resistance of a conductivity cell containing 0.001M KC1 solution at 298 K is 1500 . What is the cell constant if conductivity of 0.001M KC1 solution at 298 K is 0.146 x 10“3 S cm-1.
The resistance of a conductivity cell containing 10^-3 M KCI solution at 25^@ C is 1500 Omega . What is the cell constant If conductivity of 10^@ M KCl solution at 25^@ C is 1.5 xx 10^-4 S cm^-1 ?
The conductivity of 0.35M NaCl solution at 298K is 0.025 S/cm. Calculate its molar conductivity .
The conductivity of 0.20 MKCl solution at 298 K is 0.0248 S cm^-1 . Calculate its molar conductivity.
What is the ionization constant of an acid if the hydronium ion concentration of a 0.40 M solution is 1.40xx10^(-4) M?
The dissociation constant of a weak acid is 1.6xx10^(-5) and the molar conductivity at infinite dilution is 380xx10^(-4) S m^2mol^(-1) . If the cell constant is 0.01 m^(-1) then conductace of 0.01M acid solution is :
The resistance of a conductivity cell with 0.1 M KCl solution is found to be 200 ohm at 298K. When the same cell was filled with 0.02 M NaCl solution, the resistance at the same temperature is found to be 1100 ohm . Calculate: the cell constant of the cell in m^-1 . Given conductivity of 0.lM KCl is 1.29 Sm^(-1) ]
Resistance of a conductivity cell filled with 0.1 mol L^-1 KC1 solution is 100Omega .If the resistance of the same cell when filled with 0.02 mol L^(-1) KC1 solution is 520Omega , calculate the conductivity and molar conductivity of 0.02 mol L^(-1) KC1 solution. The conductivity of 0.1 mol L(-1) KCI solution is 1.29 S/m.
The resistance of a conductivity cell with 0.1 M KCl solution is found to be 200 ohm at 298K. When the same cell was filled with 0.02 M NaCl solution, the resistance at the same temperature is found to be 1100 ohm . Calculate: the molar conductivity of 0.02 M NaCl solution in S m^2 mol^-1 . Given: Conductivity of 0.1 M KCl solution at 298K = 1.29 S m^-1 .
Given the following molar conductivity at 25^(@) C:, HCl,426 Omega^(-1)cm^2mol^(-1) , NaCl, 126Omega^(-1)cm^2mol^(-1) , NaC(sodium crotonate), 83Omega^(_1)cm^2mol^(-1) . What is the dissciation constant of crotonic acid,if the conductivity of a 0.001 M crotonic acid solution is 3.83xx10^(-5)Omega^(-1)cm^(-1) ?